Chris Barba

Record count of all tables in a database

Here is a sql script that will give a count of all records in every table in your database. This comes from my friend David McCollough.

CREATE TABLE #sizes ([name] nvarchar(200), 
-- BOL says (20), but that obviously wrong
             [rowcount] varchar(25))
DECLARE @tablename VARCHAR (128)

DECLARE tables CURSOR FOR
   SELECT TABLE_NAME
   FROM INFORMATION_SCHEMA.TABLES
   WHERE TABLE_TYPE = 'BASE TABLE'
   order by TABLE_NAME

-- Open the cursor
OPEN tables

-- Loop through all the tables in the database
FETCH NEXT
   FROM tables
   INTO @tablename

WHILE @@FETCH_STATUS = 0
BEGIN
  --print 'Insert into #sizes Select ''' +  @tablename + ''' as [name] ,count(*) from ' + @tablename
  --exec ('Insert into #sizes Select ''' +  @tablename + ''' as [name] ,count(*) from ' + @tablename)
  --faster than select count(*)
  exec ('Insert into #sizes Select ''' +  @tablename + ''' as [name],(SELECT rows FROM sysindexes WHERE id = OBJECT_ID(''' +  @tablename + ''') AND indid < 2)')
FETCH NEXT
   FROM tables
   INTO @tablename
END

-- Close and deallocate the cursor
CLOSE tables
DEALLOCATE tables

select * from #sizes Order by [name]
drop table #sizes

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posted @ Monday, December 07, 2009 7:59 AM